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1355504424251 is a prime number
BaseRepresentation
bin10011101110011010010…
…111000001010100111011
311210120210102201100101212
4103232122113001110323
5134202033113034001
62514413220033335
7166634443333265
oct23563227012473
94716712640355
101355504424251
11482958a0069a
1219a85783284b
139aa92369823
144986cd64b35
15253d6b607bb
hex13b9a5c153b

1355504424251 has 2 divisors, whose sum is σ = 1355504424252. Its totient is φ = 1355504424250.

The previous prime is 1355504424193. The next prime is 1355504424271. The reversal of 1355504424251 is 1524244055531.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1355504424251 - 222 = 1355500229947 is a prime.

It is a super-2 number, since 2×13555044242512 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1355504424199 and 1355504424208.

It is not a weakly prime, because it can be changed into another prime (1355504424271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677752212125 + 677752212126.

It is an arithmetic number, because the mean of its divisors is an integer number (677752212126).

Almost surely, 21355504424251 is an apocalyptic number.

1355504424251 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355504424251 is an equidigital number, since it uses as much as digits as its factorization.

1355504424251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480000, while the sum is 41.

Adding to 1355504424251 its reverse (1524244055531), we get a palindrome (2879748479782).

The spelling of 1355504424251 in words is "one trillion, three hundred fifty-five billion, five hundred four million, four hundred twenty-four thousand, two hundred fifty-one".