13555101043351 has 16 divisors (see below), whose sum is σ = 16435682784000. Its totient is φ = 10913293272960.

The previous prime is 13555101043339. The next prime is 13555101043381. The reversal of 13555101043351 is 15334010155531.

13555101043351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13555101043351 - 2³⁹ = 13005345229463 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13555101043351.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13555101043301) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 114077305 + ... + 114196066.

It is an arithmetic number, because the mean of its divisors is an integer number (1027230174000).

Almost surely, 2^{13555101043351} is an apocalyptic number.

13555101043351 is a deficient number, since it is larger than the sum of its proper divisors (2880581740649).

13555101043351 is a wasteful number, since it uses less digits than its factorization.

13555101043351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 228273894.

The product of its (nonzero) digits is 67500, while the sum is 37.

Adding to 13555101043351 its reverse (15334010155531), we get a palindrome (28889111198882).

The spelling of 13555101043351 in words is "thirteen trillion, five hundred fifty-five billion, one hundred one million, forty-three thousand, three hundred fifty-one".