Base | Representation |
---|---|
bin | 1100010101000111001110… |
… | …0001101101101110000101 |
3 | 1210000000121112102200212021 |
4 | 3011101303201231232011 |
5 | 3234103414340112122 |
6 | 44455533323523141 |
7 | 2566310335134232 |
oct | 305216341555605 |
9 | 53000545380767 |
10 | 13556855004037 |
11 | 4357480250234 |
12 | 162b4ab3894b1 |
13 | 774537b127c7 |
14 | 34c226150789 |
15 | 1879a18871c7 |
hex | c547386db85 |
13556855004037 has 32 divisors (see below), whose sum is σ = 15135481670400. Its totient is φ = 12067316352000.
The previous prime is 13556855003957. The next prime is 13556855004103. The reversal of 13556855004037 is 73040055865531.
13556855004037 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13556855004037 - 239 = 13007099190149 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13556855004337) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1265925639 + ... + 1265936347.
It is an arithmetic number, because the mean of its divisors is an integer number (472983802200).
Almost surely, 213556855004037 is an apocalyptic number.
13556855004037 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
13556855004037 is a deficient number, since it is larger than the sum of its proper divisors (1578626666363).
13556855004037 is a wasteful number, since it uses less digits than its factorization.
13556855004037 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17037.
The product of its (nonzero) digits is 7560000, while the sum is 52.
The spelling of 13556855004037 in words is "thirteen trillion, five hundred fifty-six billion, eight hundred fifty-five million, four thousand, thirty-seven".
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