135601274380003 has 2 divisors, whose sum is σ = 135601274380004. Its totient is φ = 135601274380002.

The previous prime is 135601274380001. The next prime is 135601274380021. The reversal of 135601274380003 is 300083472106531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 135601274380003 - 2¹ = 135601274380001 is a prime.

It is a super-2 number, since 2×135601274380003² (a number of 29 digits) contains 22 as substring.

Together with 135601274380001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (135601274380001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67800637190001 + 67800637190002.

It is an arithmetic number, because the mean of its divisors is an integer number (67800637190002).

Almost surely, 2^{135601274380003} is an apocalyptic number.

135601274380003 is a deficient number, since it is larger than the sum of its proper divisors (1).

135601274380003 is an equidigital number, since it uses as much as digits as its factorization.

135601274380003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 43.

The spelling of 135601274380003 in words is "one hundred thirty-five trillion, six hundred one billion, two hundred seventy-four million, three hundred eighty thousand, three".