Base | Representation |
---|---|
bin | 111111001001011000… |
… | …1111100111111000011 |
3 | 110222000122122201121211 |
4 | 1332102301330333003 |
5 | 4210210234221223 |
6 | 142144035030551 |
7 | 12540312460324 |
oct | 1762261747703 |
9 | 428018581554 |
10 | 135606554563 |
11 | 525684015a7 |
12 | 2234643b457 |
13 | ca315b553c |
14 | 67c5d3c44b |
15 | 37da17ed0d |
hex | 1f92c7cfc3 |
135606554563 has 2 divisors, whose sum is σ = 135606554564. Its totient is φ = 135606554562.
The previous prime is 135606554557. The next prime is 135606554591. The reversal of 135606554563 is 365455606531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135606554563 - 213 = 135606546371 is a prime.
It is a super-2 number, since 2×1356065545632 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (135606554593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67803277281 + 67803277282.
It is an arithmetic number, because the mean of its divisors is an integer number (67803277282).
Almost surely, 2135606554563 is an apocalyptic number.
135606554563 is a deficient number, since it is larger than the sum of its proper divisors (1).
135606554563 is an equidigital number, since it uses as much as digits as its factorization.
135606554563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4860000, while the sum is 49.
The spelling of 135606554563 in words is "one hundred thirty-five billion, six hundred six million, five hundred fifty-four thousand, five hundred sixty-three".
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