Base | Representation |
---|---|
bin | 10011101111000101111… |
… | …011101010011100100111 |
3 | 11210122200101021022102012 |
4 | 103233011323222130213 |
5 | 134210032233401101 |
6 | 2515013532304435 |
7 | 166661531055161 |
oct | 23570573523447 |
9 | 4718611238365 |
10 | 1356235450151 |
11 | 4831a361122a |
12 | 19aa2061211b |
13 | 9ab7a94cb2a |
14 | 498dc097931 |
15 | 2542ae10bbb |
hex | 13bc5eea727 |
1356235450151 has 4 divisors (see below), whose sum is σ = 1356274209312. Its totient is φ = 1356196690992.
The previous prime is 1356235450103. The next prime is 1356235450183. The reversal of 1356235450151 is 1510545326531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1356235450151 - 238 = 1081357543207 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1356235450099 and 1356235450108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1356285450151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19327046 + ... + 19397091.
It is an arithmetic number, because the mean of its divisors is an integer number (339068552328).
Almost surely, 21356235450151 is an apocalyptic number.
1356235450151 is a deficient number, since it is larger than the sum of its proper divisors (38759161).
1356235450151 is an equidigital number, since it uses as much as digits as its factorization.
1356235450151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38759160.
The product of its (nonzero) digits is 270000, while the sum is 41.
The spelling of 1356235450151 in words is "one trillion, three hundred fifty-six billion, two hundred thirty-five million, four hundred fifty thousand, one hundred fifty-one".
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