Base | Representation |
---|---|
bin | 111111001010011011… |
… | …0001111110011010011 |
3 | 110222010001220122202020 |
4 | 1332110312033303103 |
5 | 4210243124002033 |
6 | 142151314222523 |
7 | 12541213320405 |
oct | 1762466176323 |
9 | 428101818666 |
10 | 135641234643 |
11 | 52585a39222 |
12 | 22355b84a43 |
13 | ca388387b5 |
14 | 67ca7a8b75 |
15 | 37dd2306b3 |
hex | 1f94d8fcd3 |
135641234643 has 32 divisors (see below), whose sum is σ = 184859539200. Its totient is φ = 88442112000.
The previous prime is 135641234633. The next prime is 135641234657. The reversal of 135641234643 is 346432146531.
It is not a de Polignac number, because 135641234643 - 24 = 135641234627 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135641234595 and 135641234604.
It is not an unprimeable number, because it can be changed into a prime (135641234633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29737083 + ... + 29741643.
It is an arithmetic number, because the mean of its divisors is an integer number (5776860600).
Almost surely, 2135641234643 is an apocalyptic number.
135641234643 is a deficient number, since it is larger than the sum of its proper divisors (49218304557).
135641234643 is a wasteful number, since it uses less digits than its factorization.
135641234643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5443.
The product of its digits is 622080, while the sum is 42.
The spelling of 135641234643 in words is "one hundred thirty-five billion, six hundred forty-one million, two hundred thirty-four thousand, six hundred forty-three".
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