13566009131 has 2 divisors, whose sum is σ = 13566009132. Its totient is φ = 13566009130.

The previous prime is 13566009103. The next prime is 13566009133. The reversal of 13566009131 is 13190066531.

It is a strong prime.

It is an emirp because it is prime and its reverse (13190066531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13566009131 is a prime.

It is a super-3 number, since 3×13566009131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13566009133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13566009091 and 13566009100.

It is not a weakly prime, because it can be changed into another prime (13566009133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6783004565 + 6783004566.

It is an arithmetic number, because the mean of its divisors is an integer number (6783004566).

Almost surely, 2^13566009131 is an apocalyptic number.

13566009131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13566009131 is an equidigital number, since it uses as much as digits as its factorization.

13566009131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14580, while the sum is 35.

The spelling of 13566009131 in words is "thirteen billion, five hundred sixty-six million, nine thousand, one hundred thirty-one".