Base | Representation |
---|---|
bin | 111111001011100001… |
… | …0100101101111111001 |
3 | 110222012122010210012211 |
4 | 1332113002211233321 |
5 | 4210332033242242 |
6 | 142155110535121 |
7 | 12542141116135 |
oct | 1762702455771 |
9 | 428178123184 |
10 | 135678024697 |
11 | 525a4787126 |
12 | 223663674a1 |
13 | ca4334a267 |
14 | 67d16243c5 |
15 | 37e159b317 |
hex | 1f970a5bf9 |
135678024697 has 2 divisors, whose sum is σ = 135678024698. Its totient is φ = 135678024696.
The previous prime is 135678024689. The next prime is 135678024721. The reversal of 135678024697 is 796420876531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 134721297936 + 956726761 = 367044^2 + 30931^2 .
It is a cyclic number.
It is not a de Polignac number, because 135678024697 - 23 = 135678024689 is a prime.
It is not a weakly prime, because it can be changed into another prime (135678024497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67839012348 + 67839012349.
It is an arithmetic number, because the mean of its divisors is an integer number (67839012349).
It is a 1-persistent number, because it is pandigital, but 2⋅135678024697 = 271356049394 is not.
Almost surely, 2135678024697 is an apocalyptic number.
It is an amenable number.
135678024697 is a deficient number, since it is larger than the sum of its proper divisors (1).
135678024697 is an equidigital number, since it uses as much as digits as its factorization.
135678024697 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15240960, while the sum is 58.
The spelling of 135678024697 in words is "one hundred thirty-five billion, six hundred seventy-eight million, twenty-four thousand, six hundred ninety-seven".
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