Base | Representation |
---|---|
bin | 10011101111101111101… |
… | …010111010010011111011 |
3 | 11210201111011220210000210 |
4 | 103233233222322103323 |
5 | 134213001014424010 |
6 | 2515211225202203 |
7 | 200015063105064 |
oct | 23575752722373 |
9 | 4721434823023 |
10 | 1356935701755 |
11 | 483522912667 |
12 | 19ab97030363 |
13 | 9ac5ca498aa |
14 | 4996709956b |
15 | 2546c632b20 |
hex | 13befaba4fb |
1356935701755 has 8 divisors (see below), whose sum is σ = 2171097122832. Its totient is φ = 723699040928.
The previous prime is 1356935701753. The next prime is 1356935701817. The reversal of 1356935701755 is 5571075396531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1356935701755 - 21 = 1356935701753 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1356935701695 and 1356935701704.
It is not an unprimeable number, because it can be changed into a prime (1356935701753) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45231190044 + ... + 45231190073.
It is an arithmetic number, because the mean of its divisors is an integer number (271387140354).
Almost surely, 21356935701755 is an apocalyptic number.
1356935701755 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1356935701755 is a deficient number, since it is larger than the sum of its proper divisors (814161421077).
1356935701755 is an equidigital number, since it uses as much as digits as its factorization.
1356935701755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90462380125.
The product of its (nonzero) digits is 14883750, while the sum is 57.
The spelling of 1356935701755 in words is "one trillion, three hundred fifty-six billion, nine hundred thirty-five million, seven hundred one thousand, seven hundred fifty-five".
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