Base | Representation |
---|---|
bin | 111111001101000100… |
… | …1000011100000101010 |
3 | 110222100021001000001011 |
4 | 1332122021003200222 |
5 | 4210433343113424 |
6 | 142204210014134 |
7 | 12543342253510 |
oct | 1763211034052 |
9 | 428307030034 |
10 | 135730051114 |
11 | 52621091369 |
12 | 2237b87734a |
13 | ca51064b18 |
14 | 67d84c84b0 |
15 | 37e5e26694 |
hex | 1f9a24382a |
135730051114 has 8 divisors (see below), whose sum is σ = 232680087648. Its totient is φ = 58170021900.
The previous prime is 135730051111. The next prime is 135730051141. The reversal of 135730051114 is 411150037531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not an unprimeable number, because it can be changed into a prime (135730051111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4847501812 + ... + 4847501839.
It is an arithmetic number, because the mean of its divisors is an integer number (29085010956).
Almost surely, 2135730051114 is an apocalyptic number.
135730051114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
135730051114 is a deficient number, since it is larger than the sum of its proper divisors (96950036534).
135730051114 is an equidigital number, since it uses as much as digits as its factorization.
135730051114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9695003660.
The product of its (nonzero) digits is 6300, while the sum is 31.
Adding to 135730051114 its reverse (411150037531), we get a palindrome (546880088645).
The spelling of 135730051114 in words is "one hundred thirty-five billion, seven hundred thirty million, fifty-one thousand, one hundred fourteen".
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