Base | Representation |
---|---|
bin | 1100010110000011100011… |
… | …1000000111010001001001 |
3 | 1210001120102020211220201012 |
4 | 3011200320320013101021 |
5 | 3234340102011424124 |
6 | 44511212401533305 |
7 | 2600422565653463 |
oct | 305407070072111 |
9 | 53046366756635 |
10 | 13573050889289 |
11 | 4363331418571 |
12 | 163266b344235 |
13 | 775c19342168 |
14 | 34cd21113133 |
15 | 1880ed672e0e |
hex | c5838e07449 |
13573050889289 has 2 divisors, whose sum is σ = 13573050889290. Its totient is φ = 13573050889288.
The previous prime is 13573050889267. The next prime is 13573050889291. The reversal of 13573050889289 is 98298805037531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13559576322889 + 13474566400 = 3682333^2 + 116080^2 .
It is a cyclic number.
It is not a de Polignac number, because 13573050889289 - 28 = 13573050889033 is a prime.
Together with 13573050889291, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13573058889289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6786525444644 + 6786525444645.
It is an arithmetic number, because the mean of its divisors is an integer number (6786525444645).
Almost surely, 213573050889289 is an apocalyptic number.
It is an amenable number.
13573050889289 is a deficient number, since it is larger than the sum of its proper divisors (1).
13573050889289 is an equidigital number, since it uses as much as digits as its factorization.
13573050889289 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 130636800, while the sum is 68.
The spelling of 13573050889289 in words is "thirteen trillion, five hundred seventy-three billion, fifty million, eight hundred eighty-nine thousand, two hundred eighty-nine".
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