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135770060117047 is a prime number
BaseRepresentation
bin11110110111101101101110…
…001101000101010000110111
3122210201111020221002111212211
4132313231232031011100313
5120243424040342221142
61200431523215154251
740412030441362306
oct3667555615052067
9583644227074784
10135770060117047
113a295839466264
1213289192515987
135a9b0a581c035
14257543d83043d
1510a6a568aa917
hex7b7b6e345437

135770060117047 has 2 divisors, whose sum is σ = 135770060117048. Its totient is φ = 135770060117046.

The previous prime is 135770060117033. The next prime is 135770060117053. The reversal of 135770060117047 is 740711060077531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135770060117047 - 231 = 135767912633399 is a prime.

It is a super-3 number, since 3×1357700601170473 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135770060117647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67885030058523 + 67885030058524.

It is an arithmetic number, because the mean of its divisors is an integer number (67885030058524).

Almost surely, 2135770060117047 is an apocalyptic number.

135770060117047 is a deficient number, since it is larger than the sum of its proper divisors (1).

135770060117047 is an equidigital number, since it uses as much as digits as its factorization.

135770060117047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864360, while the sum is 49.

The spelling of 135770060117047 in words is "one hundred thirty-five trillion, seven hundred seventy billion, sixty million, one hundred seventeen thousand, forty-seven".