Base | Representation |
---|---|
bin | 11110110111101101101110… |
… | …001101000101010000110111 |
3 | 122210201111020221002111212211 |
4 | 132313231232031011100313 |
5 | 120243424040342221142 |
6 | 1200431523215154251 |
7 | 40412030441362306 |
oct | 3667555615052067 |
9 | 583644227074784 |
10 | 135770060117047 |
11 | 3a295839466264 |
12 | 13289192515987 |
13 | 5a9b0a581c035 |
14 | 257543d83043d |
15 | 10a6a568aa917 |
hex | 7b7b6e345437 |
135770060117047 has 2 divisors, whose sum is σ = 135770060117048. Its totient is φ = 135770060117046.
The previous prime is 135770060117033. The next prime is 135770060117053. The reversal of 135770060117047 is 740711060077531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135770060117047 - 231 = 135767912633399 is a prime.
It is a super-3 number, since 3×1357700601170473 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135770060117647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67885030058523 + 67885030058524.
It is an arithmetic number, because the mean of its divisors is an integer number (67885030058524).
Almost surely, 2135770060117047 is an apocalyptic number.
135770060117047 is a deficient number, since it is larger than the sum of its proper divisors (1).
135770060117047 is an equidigital number, since it uses as much as digits as its factorization.
135770060117047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864360, while the sum is 49.
The spelling of 135770060117047 in words is "one hundred thirty-five trillion, seven hundred seventy billion, sixty million, one hundred seventeen thousand, forty-seven".
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