Base | Representation |
---|---|
bin | 11110111011000100010111… |
… | …101001110001100011001001 |
3 | 122211112112011012121101202221 |
4 | 132323010113221301203021 |
5 | 120311213044240122130 |
6 | 1201125441150454041 |
7 | 40434500033255425 |
oct | 3673042751614311 |
9 | 584475135541687 |
10 | 136000536254665 |
11 | 3a37455a209755 |
12 | 13305994504321 |
13 | 5ab6a45a51c24 |
14 | 258266529db85 |
15 | 10aca4565b87a |
hex | 7bb117a718c9 |
136000536254665 has 16 divisors (see below), whose sum is σ = 167632245821520. Its totient is φ = 105846756376320.
The previous prime is 136000536254657. The next prime is 136000536254711. The reversal of 136000536254665 is 566452635000631.
It can be written as a sum of positive squares in 8 ways, for example, as 14985817807104 + 121014718447561 = 3871152^2 + 11000669^2 .
It is not a de Polignac number, because 136000536254665 - 23 = 136000536254657 is a prime.
It is a super-2 number, since 2×1360005362546652 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44060466 + ... + 47045995.
It is an arithmetic number, because the mean of its divisors is an integer number (10477015363845).
Almost surely, 2136000536254665 is an apocalyptic number.
It is an amenable number.
136000536254665 is a deficient number, since it is larger than the sum of its proper divisors (31631709566855).
136000536254665 is an equidigital number, since it uses as much as digits as its factorization.
136000536254665 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91114572.
The product of its (nonzero) digits is 11664000, while the sum is 52.
The spelling of 136000536254665 in words is "one hundred thirty-six trillion, five hundred thirty-six million, two hundred fifty-four thousand, six hundred sixty-five".
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