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136000536254711 is a prime number
BaseRepresentation
bin11110111011000100010111…
…101001110001100011110111
3122211112112011012121101211122
4132323010113221301203313
5120311213044240122321
61201125441150454155
740434500033255522
oct3673042751614367
9584475135541748
10136000536254711
113a37455a209797
121330599450435b
135ab6a45a51c5b
14258266529dbb9
1510aca4565b8ab
hex7bb117a718f7

136000536254711 has 2 divisors, whose sum is σ = 136000536254712. Its totient is φ = 136000536254710.

The previous prime is 136000536254657. The next prime is 136000536254717. The reversal of 136000536254711 is 117452635000631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 136000536254711 - 226 = 136000469145847 is a prime.

It is a super-2 number, since 2×1360005362547112 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136000536254717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68000268127355 + 68000268127356.

It is an arithmetic number, because the mean of its divisors is an integer number (68000268127356).

Almost surely, 2136000536254711 is an apocalyptic number.

136000536254711 is a deficient number, since it is larger than the sum of its proper divisors (1).

136000536254711 is an equidigital number, since it uses as much as digits as its factorization.

136000536254711 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 453600, while the sum is 44.

The spelling of 136000536254711 in words is "one hundred thirty-six trillion, five hundred thirty-six million, two hundred fifty-four thousand, seven hundred eleven".