Base | Representation |
---|---|
bin | 11110111011000101001110… |
… | …110111100100000010010011 |
3 | 122211112121112202201102220211 |
4 | 132323011032313210002103 |
5 | 120311221443412204321 |
6 | 1201130113121544551 |
7 | 40434532012230103 |
oct | 3673051667440223 |
9 | 584477482642824 |
10 | 136001462616211 |
11 | 3a374995106905 |
12 | 13305bb27a5157 |
13 | 5ab6b6294845a |
14 | 258271231d203 |
15 | 10aca9bb440e1 |
hex | 7bb14ede4093 |
136001462616211 has 2 divisors, whose sum is σ = 136001462616212. Its totient is φ = 136001462616210.
The previous prime is 136001462616197. The next prime is 136001462616221. The reversal of 136001462616211 is 112616264100631.
It is a strong prime.
It is an emirp because it is prime and its reverse (112616264100631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 136001462616211 - 217 = 136001462485139 is a prime.
It is not a weakly prime, because it can be changed into another prime (136001462616221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68000731308105 + 68000731308106.
It is an arithmetic number, because the mean of its divisors is an integer number (68000731308106).
Almost surely, 2136001462616211 is an apocalyptic number.
136001462616211 is a deficient number, since it is larger than the sum of its proper divisors (1).
136001462616211 is an equidigital number, since it uses as much as digits as its factorization.
136001462616211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 40.
The spelling of 136001462616211 in words is "one hundred thirty-six trillion, one billion, four hundred sixty-two million, six hundred sixteen thousand, two hundred eleven".
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