Base | Representation |
---|---|
bin | 1100010111101010000000… |
… | …1010010000011010000100 |
3 | 1210011012101221212102020101 |
4 | 3011322200022100122010 |
5 | 3240312413144033330 |
6 | 44532001422213444 |
7 | 2602415252216020 |
oct | 305724012203204 |
9 | 53135357772211 |
10 | 13600553502340 |
11 | 4373a64982842 |
12 | 1637a65a24284 |
13 | 7786b01b12ac |
14 | 3503ad9cb380 |
15 | 188bacdda4ca |
hex | c5ea0290684 |
13600553502340 has 24 divisors (see below), whose sum is σ = 32641328405952. Its totient is φ = 4663046915040.
The previous prime is 13600553502329. The next prime is 13600553502343. The reversal of 13600553502340 is 4320535500631.
It is a self number, because there is not a number n which added to its sum of digits gives 13600553502340.
It is not an unprimeable number, because it can be changed into a prime (13600553502343) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48573405226 + ... + 48573405505.
It is an arithmetic number, because the mean of its divisors is an integer number (1360055350248).
Almost surely, 213600553502340 is an apocalyptic number.
13600553502340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13600553502340 is an abundant number, since it is smaller than the sum of its proper divisors (19040774903612).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13600553502340 is a wasteful number, since it uses less digits than its factorization.
13600553502340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97146810747 (or 97146810745 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 37.
The spelling of 13600553502340 in words is "thirteen trillion, six hundred billion, five hundred fifty-three million, five hundred two thousand, three hundred forty".
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