Base | Representation |
---|---|
bin | 11001010101010111… |
… | …01100010000010011 |
3 | 1022002212200022022012 |
4 | 30222223230100103 |
5 | 210323323422134 |
6 | 10125340333135 |
7 | 661021402421 |
oct | 145253542023 |
9 | 38085608265 |
10 | 13600998419 |
11 | 584a455468 |
12 | 2776b441ab |
13 | 1389a59b78 |
14 | 9304d2111 |
15 | 5490ba6ce |
hex | 32aaec413 |
13600998419 has 2 divisors, whose sum is σ = 13600998420. Its totient is φ = 13600998418.
The previous prime is 13600998401. The next prime is 13600998421. The reversal of 13600998419 is 91489900631.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13600998419 is a prime.
It is a super-2 number, since 2×136009984192 (a number of 21 digits) contains 22 as substring.
Together with 13600998421, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13600998479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6800499209 + 6800499210.
It is an arithmetic number, because the mean of its divisors is an integer number (6800499210).
Almost surely, 213600998419 is an apocalyptic number.
13600998419 is a deficient number, since it is larger than the sum of its proper divisors (1).
13600998419 is an equidigital number, since it uses as much as digits as its factorization.
13600998419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 419904, while the sum is 50.
The spelling of 13600998419 in words is "thirteen billion, six hundred million, nine hundred ninety-eight thousand, four hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •