Base | Representation |
---|---|
bin | 11110111011001111001100… |
… | …010111110110110111110011 |
3 | 122211120122011011021210111102 |
4 | 132323033030113312313303 |
5 | 120311410344442343223 |
6 | 1201135042312435015 |
7 | 40435361034020345 |
oct | 3673171427666763 |
9 | 584518134253442 |
10 | 136012158168563 |
11 | 3a379483502676 |
12 | 133080986a8a6b |
13 | 5ab7b78778761 |
14 | 25830489bd295 |
15 | 10acec5ae6928 |
hex | 7bb3cc5f6df3 |
136012158168563 has 2 divisors, whose sum is σ = 136012158168564. Its totient is φ = 136012158168562.
The previous prime is 136012158168479. The next prime is 136012158168619. The reversal of 136012158168563 is 365861851210631.
It is an a-pointer prime, because the next prime (136012158168619) can be obtained adding 136012158168563 to its sum of digits (56).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136012158168563 - 210 = 136012158167539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 136012158168499 and 136012158168508.
It is not a weakly prime, because it can be changed into another prime (136012158168163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68006079084281 + 68006079084282.
It is an arithmetic number, because the mean of its divisors is an integer number (68006079084282).
Almost surely, 2136012158168563 is an apocalyptic number.
136012158168563 is a deficient number, since it is larger than the sum of its proper divisors (1).
136012158168563 is an equidigital number, since it uses as much as digits as its factorization.
136012158168563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6220800, while the sum is 56.
The spelling of 136012158168563 in words is "one hundred thirty-six trillion, twelve billion, one hundred fifty-eight million, one hundred sixty-eight thousand, five hundred sixty-three".
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