Base | Representation |
---|---|
bin | 11001010101011001… |
… | …00111101111000011 |
3 | 1022002220010200111121 |
4 | 30222230213233003 |
5 | 210323404221201 |
6 | 10125345453111 |
7 | 661023435625 |
oct | 145254475703 |
9 | 38086120447 |
10 | 13601242051 |
11 | 584a601511 |
12 | 2777041197 |
13 | 1389b13a27 |
14 | 930556c15 |
15 | 5491179a1 |
hex | 32ab27bc3 |
13601242051 has 4 divisors (see below), whose sum is σ = 13932979704. Its totient is φ = 13269504400.
The previous prime is 13601242009. The next prime is 13601242087. The reversal of 13601242051 is 15024210631.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13601242051 - 213 = 13601233859 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13601242351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165868765 + ... + 165868846.
It is an arithmetic number, because the mean of its divisors is an integer number (3483244926).
Almost surely, 213601242051 is an apocalyptic number.
13601242051 is a deficient number, since it is larger than the sum of its proper divisors (331737653).
13601242051 is an equidigital number, since it uses as much as digits as its factorization.
13601242051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 331737652.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13601242051 its reverse (15024210631), we get a palindrome (28625452682).
The spelling of 13601242051 in words is "thirteen billion, six hundred one million, two hundred forty-two thousand, fifty-one".
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