Base | Representation |
---|---|
bin | 11110111011010001001110… |
… | …011011111000011001001010 |
3 | 122211120211210020021121012111 |
4 | 132323101032123320121022 |
5 | 120311424332101331300 |
6 | 1201140043022332534 |
7 | 40435466101345240 |
oct | 3673211633703112 |
9 | 584524706247174 |
10 | 136014340261450 |
11 | 3a37a3a3211322 |
12 | 133085a742a14a |
13 | 5ab813587a491 |
14 | 25831b4718790 |
15 | 10ad0a24779ba |
hex | 7bb44e6f864a |
136014340261450 has 48 divisors (see below), whose sum is σ = 291780173266560. Its totient is φ = 46205657910720.
The previous prime is 136014340261427. The next prime is 136014340261517. The reversal of 136014340261450 is 54162043410631.
It is a super-2 number, since 2×1360143402614502 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1782587542 + ... + 1782663841.
It is an arithmetic number, because the mean of its divisors is an integer number (6078753609720).
Almost surely, 2136014340261450 is an apocalyptic number.
136014340261450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
136014340261450 is an abundant number, since it is smaller than the sum of its proper divisors (155765833005110).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136014340261450 is a wasteful number, since it uses less digits than its factorization.
136014340261450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3565251511 (or 3565251506 counting only the distinct ones).
The product of its (nonzero) digits is 207360, while the sum is 40.
The spelling of 136014340261450 in words is "one hundred thirty-six trillion, fourteen billion, three hundred forty million, two hundred sixty-one thousand, four hundred fifty".
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