Search a number
-
+
136014737147851 = 870831561897697
BaseRepresentation
bin11110111011010001100110…
…000101111000011111001011
3122211120212210220002111222211
4132323101212011320133023
5120311431140202212401
61201140150241125551
740435511661001402
oct3673214605703713
9584525726074884
10136014737147851
113a37a58724aa11
12133086983298b7
135ab8199b6b7c3
14258321130c639
1510ad0c7223951
hex7bb4661787cb

136014737147851 has 4 divisors (see below), whose sum is σ = 136016299132632. Its totient is φ = 136013175163072.

The previous prime is 136014737147789. The next prime is 136014737147897. The reversal of 136014737147851 is 158741737410631.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 136014737147851 - 233 = 136006147213259 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (136014737147251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 780861766 + ... + 781035931.

It is an arithmetic number, because the mean of its divisors is an integer number (34004074783158).

Almost surely, 2136014737147851 is an apocalyptic number.

136014737147851 is a deficient number, since it is larger than the sum of its proper divisors (1561984781).

136014737147851 is an equidigital number, since it uses as much as digits as its factorization.

136014737147851 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1561984780.

The product of its (nonzero) digits is 11854080, while the sum is 58.

The spelling of 136014737147851 in words is "one hundred thirty-six trillion, fourteen billion, seven hundred thirty-seven million, one hundred forty-seven thousand, eight hundred fifty-one".

Divisors: 1 87083 1561897697 136014737147851