1360204012800 has 648 divisors, whose sum is σ = 5154443427840. Its totient is φ = 350977536000.

The previous prime is 1360204012799. The next prime is 1360204012819. The reversal of 1360204012800 is 82104020631.

1360204012800 is a `hidden beast` number, since 1 + 3 + 602 + 0 + 40 + 12 + 8 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 166056705 + ... + 166064895.

Almost surely, 2^{1360204012800} is an apocalyptic number.

1360204012800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1360204012800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2577221713920).

1360204012800 is an abundant number, since it is smaller than the sum of its proper divisors (3794239415040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1360204012800 is an equidigital number, since it uses as much as digits as its factorization.

1360204012800 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8288 (or 8232 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

The spelling of 1360204012800 in words is "one trillion, three hundred sixty billion, two hundred four million, twelve thousand, eight hundred".