Base | Representation |
---|---|
bin | 10000001101110… |
… | …01000101110001 |
3 | 100110221202102222 |
4 | 20012321011301 |
5 | 234310240213 |
6 | 21255250425 |
7 | 3241121456 |
oct | 1006710561 |
9 | 313852388 |
10 | 136024433 |
11 | 6a867196 |
12 | 39679a15 |
13 | 2224793c |
14 | 140cb82d |
15 | be1d808 |
hex | 81b9171 |
136024433 has 2 divisors, whose sum is σ = 136024434. Its totient is φ = 136024432.
The previous prime is 136024417. The next prime is 136024453. The reversal of 136024433 is 334420631.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 117765904 + 18258529 = 10852^2 + 4273^2 .
It is an emirp because it is prime and its reverse (334420631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 136024433 - 24 = 136024417 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is equal to p7700039 and since 136024433 and 7700039 have the same sum of digits, it is a Honaker prime.
It is not a weakly prime, because it can be changed into another prime (136024453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68012216 + 68012217.
It is an arithmetic number, because the mean of its divisors is an integer number (68012217).
Almost surely, 2136024433 is an apocalyptic number.
It is an amenable number.
136024433 is a deficient number, since it is larger than the sum of its proper divisors (1).
136024433 is an equidigital number, since it uses as much as digits as its factorization.
136024433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
The square root of 136024433 is about 11662.9512988780. The cubic root of 136024433 is about 514.2871124264.
The spelling of 136024433 in words is "one hundred thirty-six million, twenty-four thousand, four hundred thirty-three".
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