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13603425545077 is a prime number
BaseRepresentation
bin1100010111110100101101…
…0110001110101101110101
31210011110211010010022012121
43011331023112032231311
53240334303414420302
644533154420115541
72602546365166324
oct305751326165565
953143733108177
1013603425545077
1143751a9096a85
121638527835bb1
13778a4a213a74
143505a32060bb
15188cca105e37
hexc5f4b58eb75

13603425545077 has 2 divisors, whose sum is σ = 13603425545078. Its totient is φ = 13603425545076.

The previous prime is 13603425545069. The next prime is 13603425545111. The reversal of 13603425545077 is 77054552430631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7104362490801 + 6499063054276 = 2665401^2 + 2549326^2 .

It is an emirp because it is prime and its reverse (77054552430631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13603425545077 - 23 = 13603425545069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13603425545977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6801712772538 + 6801712772539.

It is an arithmetic number, because the mean of its divisors is an integer number (6801712772539).

Almost surely, 213603425545077 is an apocalyptic number.

It is an amenable number.

13603425545077 is a deficient number, since it is larger than the sum of its proper divisors (1).

13603425545077 is an equidigital number, since it uses as much as digits as its factorization.

13603425545077 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10584000, while the sum is 52.

The spelling of 13603425545077 in words is "thirteen trillion, six hundred three billion, four hundred twenty-five million, five hundred forty-five thousand, seventy-seven".