Base | Representation |
---|---|
bin | 11110111011100100101010… |
… | …110000000111010010100011 |
3 | 122211122211200010110102211212 |
4 | 132323210222300013102203 |
5 | 120312300110401001201 |
6 | 1201153414331100335 |
7 | 40440135322651232 |
oct | 3673445260072243 |
9 | 584584603412755 |
10 | 136035216422051 |
11 | 3a38823626a811 |
12 | 133106528a16ab |
13 | 5aba0b192292b |
14 | 25841d5112b19 |
15 | 10ad8c50b1abb |
hex | 7bb92ac074a3 |
136035216422051 has 2 divisors, whose sum is σ = 136035216422052. Its totient is φ = 136035216422050.
The previous prime is 136035216422023. The next prime is 136035216422069. The reversal of 136035216422051 is 150224612530631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136035216422051 - 26 = 136035216421987 is a prime.
It is not a weakly prime, because it can be changed into another prime (136035216427051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68017608211025 + 68017608211026.
It is an arithmetic number, because the mean of its divisors is an integer number (68017608211026).
Almost surely, 2136035216422051 is an apocalyptic number.
136035216422051 is a deficient number, since it is larger than the sum of its proper divisors (1).
136035216422051 is an equidigital number, since it uses as much as digits as its factorization.
136035216422051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 41.
Adding to 136035216422051 its reverse (150224612530631), we get a palindrome (286259828952682).
The spelling of 136035216422051 in words is "one hundred thirty-six trillion, thirty-five billion, two hundred sixteen million, four hundred twenty-two thousand, fifty-one".
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