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136035216422023 is a prime number
BaseRepresentation
bin11110111011100100101010…
…110000000111010010000111
3122211122211200010110102210211
4132323210222300013102013
5120312300110401001043
61201153414331100251
740440135322651162
oct3673445260072207
9584584603412724
10136035216422023
113a38823626a796
12133106528a1687
135aba0b1922909
1425841d5112ad9
1510ad8c50b1a9d
hex7bb92ac07487

136035216422023 has 2 divisors, whose sum is σ = 136035216422024. Its totient is φ = 136035216422022.

The previous prime is 136035216421987. The next prime is 136035216422051. The reversal of 136035216422023 is 320224612530631.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136035216422023 is a prime.

It is a super-2 number, since 2×1360352164220232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136035216432023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68017608211011 + 68017608211012.

It is an arithmetic number, because the mean of its divisors is an integer number (68017608211012).

Almost surely, 2136035216422023 is an apocalyptic number.

136035216422023 is a deficient number, since it is larger than the sum of its proper divisors (1).

136035216422023 is an equidigital number, since it uses as much as digits as its factorization.

136035216422023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 136035216422023 its reverse (320224612530631), we get a palindrome (456259828952654).

The spelling of 136035216422023 in words is "one hundred thirty-six trillion, thirty-five billion, two hundred sixteen million, four hundred twenty-two thousand, twenty-three".