1360404331007 has 2 divisors, whose sum is σ = 1360404331008. Its totient is φ = 1360404331006.

The previous prime is 1360404330983. The next prime is 1360404331019. The reversal of 1360404331007 is 7001334040631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1360404331007 - 2⁸ = 1360404330751 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1360404331037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680202165503 + 680202165504.

It is an arithmetic number, because the mean of its divisors is an integer number (680202165504).

Almost surely, 2^{1360404331007} is an apocalyptic number.

1360404331007 is a deficient number, since it is larger than the sum of its proper divisors (1).

1360404331007 is an equidigital number, since it uses as much as digits as its factorization.

1360404331007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 32.

Adding to 1360404331007 its reverse (7001334040631), we get a palindrome (8361738371638).

The spelling of 1360404331007 in words is "one trillion, three hundred sixty billion, four hundred four million, three hundred thirty-one thousand, seven".