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1360404331189 is a prime number
BaseRepresentation
bin10011110010111110011…
…010101011101010110101
311211001102220202102002121
4103302332122223222311
5134242102002044224
62520543334035541
7200200042010251
oct23627632535265
94731386672077
101360404331189
11484a42863262
1219b7a47a8bb1
139b393551447
1449bb5a0d261
15255c1de4be4
hex13cbe6abab5

1360404331189 has 2 divisors, whose sum is σ = 1360404331190. Its totient is φ = 1360404331188.

The previous prime is 1360404331103. The next prime is 1360404331217. The reversal of 1360404331189 is 9811334040631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1053230112900 + 307174218289 = 1026270^2 + 554233^2 .

It is a cyclic number.

It is not a de Polignac number, because 1360404331189 - 27 = 1360404331061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1360404331589) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680202165594 + 680202165595.

It is an arithmetic number, because the mean of its divisors is an integer number (680202165595).

Almost surely, 21360404331189 is an apocalyptic number.

It is an amenable number.

1360404331189 is a deficient number, since it is larger than the sum of its proper divisors (1).

1360404331189 is an equidigital number, since it uses as much as digits as its factorization.

1360404331189 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 43.

The spelling of 1360404331189 in words is "one trillion, three hundred sixty billion, four hundred four million, three hundred thirty-one thousand, one hundred eighty-nine".