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1360404354441 = 31141224374377
BaseRepresentation
bin10011110010111110011…
…010110001010110001001
311211001102220210120222210
4103302332122301112021
5134242102003320231
62520543334335333
7200200042135116
oct23627632612611
94731386716883
101360404354441
11484a42879780
1219b7a47ba549
139b39355bbc2
1449bb5a1790d
15255c1deba46
hex13cbe6b1589

1360404354441 has 8 divisors (see below), whose sum is σ = 1978769970144. Its totient is φ = 824487487520.

The previous prime is 1360404354437. The next prime is 1360404354479. The reversal of 1360404354441 is 1444534040631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1360404354441 - 22 = 1360404354437 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1360404354441.

It is not an unprimeable number, because it can be changed into a prime (1360404354431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20612187156 + ... + 20612187221.

It is an arithmetic number, because the mean of its divisors is an integer number (247346246268).

Almost surely, 21360404354441 is an apocalyptic number.

1360404354441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1360404354441 is a deficient number, since it is larger than the sum of its proper divisors (618365615703).

1360404354441 is a wasteful number, since it uses less digits than its factorization.

1360404354441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41224374391.

The product of its (nonzero) digits is 276480, while the sum is 39.

The spelling of 1360404354441 in words is "one trillion, three hundred sixty billion, four hundred four million, three hundred fifty-four thousand, four hundred forty-one".

Divisors: 1 3 11 33 41224374377 123673123131 453468118147 1360404354441