Base | Representation |
---|---|
bin | 10011110010111110011… |
… | …011110101101001110111 |
3 | 11211001102221022210210101 |
4 | 103302332123311221313 |
5 | 134242102041243411 |
6 | 2520543344334531 |
7 | 200200044411616 |
oct | 23627633655167 |
9 | 4731387283711 |
10 | 1360404634231 |
11 | 484a42a4aa05 |
12 | 19b7a4914447 |
13 | 9b393629366 |
14 | 49bb5a8b87d |
15 | 255c1e548c1 |
hex | 13cbe6f5a77 |
1360404634231 has 2 divisors, whose sum is σ = 1360404634232. Its totient is φ = 1360404634230.
The previous prime is 1360404634223. The next prime is 1360404634247. The reversal of 1360404634231 is 1324364040631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1360404634231 - 23 = 1360404634223 is a prime.
It is a super-2 number, since 2×13604046342312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1360404634201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680202317115 + 680202317116.
It is an arithmetic number, because the mean of its divisors is an integer number (680202317116).
Almost surely, 21360404634231 is an apocalyptic number.
1360404634231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1360404634231 is an equidigital number, since it uses as much as digits as its factorization.
1360404634231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 37.
Adding to 1360404634231 its reverse (1324364040631), we get a palindrome (2684768674862).
The spelling of 1360404634231 in words is "one trillion, three hundred sixty billion, four hundred four million, six hundred thirty-four thousand, two hundred thirty-one".
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