1360476144113 has 2 divisors, whose sum is σ = 1360476144114. Its totient is φ = 1360476144112.

The previous prime is 1360476144107. The next prime is 1360476144119. The reversal of 1360476144113 is 3114416740631.

It is a balanced prime because it is at equal distance from previous prime (1360476144107) and next prime (1360476144119).

It can be written as a sum of positive squares in only one way, i.e., 1328643518224 + 31832625889 = 1152668^2 + 178417^2 .

It is a cyclic number.

It is not a de Polignac number, because 1360476144113 - 2¹² = 1360476140017 is a prime.

It is not a weakly prime, because it can be changed into another prime (1360476144119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680238072056 + 680238072057.

It is an arithmetic number, because the mean of its divisors is an integer number (680238072057).

Almost surely, 2^{1360476144113} is an apocalyptic number.

It is an amenable number.

1360476144113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1360476144113 is an equidigital number, since it uses as much as digits as its factorization.

1360476144113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 41.

The spelling of 1360476144113 in words is "one trillion, three hundred sixty billion, four hundred seventy-six million, one hundred forty-four thousand, one hundred thirteen".