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136047937 is a prime number
BaseRepresentation
bin10000001101111…
…10110101000001
3100110222221200111
420012332311001
5234312013222
621255551321
73241250134
oct1006766501
9313887614
10136047937
116a882913
123968b541
132225554c
14140d621b
15be25777
hex81bed41

136047937 has 2 divisors, whose sum is σ = 136047938. Its totient is φ = 136047936.

The previous prime is 136047929. The next prime is 136047973. The reversal of 136047937 is 739740631.

Together with next prime (136047973) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131882256 + 4165681 = 11484^2 + 2041^2 .

It is a cyclic number.

It is not a de Polignac number, because 136047937 - 23 = 136047929 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 136047937.

It is not a weakly prime, because it can be changed into another prime (136047907) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68023968 + 68023969.

It is an arithmetic number, because the mean of its divisors is an integer number (68023969).

Almost surely, 2136047937 is an apocalyptic number.

It is an amenable number.

136047937 is a deficient number, since it is larger than the sum of its proper divisors (1).

136047937 is an equidigital number, since it uses as much as digits as its factorization.

136047937 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 95256, while the sum is 40.

The square root of 136047937 is about 11663.9588905311. The cubic root of 136047937 is about 514.3167323701.

The spelling of 136047937 in words is "one hundred thirty-six million, forty-seven thousand, nine hundred thirty-seven".