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1360564541341 = 1413719624071
BaseRepresentation
bin10011110011000111111…
…101110101011110011101
311211001212002012221002221
4103303013331311132131
5134242414010310331
62521011255545341
7200204025533245
oct23630775653635
94731762187087
101360564541341
11485015239545
1219b82a38b251
139b3ba7b6755
1449bccdd4b25
15255d0ede711
hex13cc7f7579d

1360564541341 has 4 divisors (see below), whose sum is σ = 1360574306784. Its totient is φ = 1360554775900.

The previous prime is 1360564541339. The next prime is 1360564541377. The reversal of 1360564541341 is 1431454650631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1360564541341 - 21 = 1360564541339 is a prime.

It is a super-2 number, since 2×13605645413412 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1360564545341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4670665 + ... + 4953406.

It is an arithmetic number, because the mean of its divisors is an integer number (340143576696).

Almost surely, 21360564541341 is an apocalyptic number.

It is an amenable number.

1360564541341 is a deficient number, since it is larger than the sum of its proper divisors (9765443).

1360564541341 is an equidigital number, since it uses as much as digits as its factorization.

1360564541341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9765442.

The product of its (nonzero) digits is 518400, while the sum is 43.

The spelling of 1360564541341 in words is "one trillion, three hundred sixty billion, five hundred sixty-four million, five hundred forty-one thousand, three hundred forty-one".

Divisors: 1 141371 9624071 1360564541341