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13608948345 = 35907263223
BaseRepresentation
bin11001010110010100…
…00001001001111001
31022010102122012112220
430223022001021321
5210332342321340
610130222554253
7661146103146
oct145312011171
938112565486
1013608948345
115853995353
122779738989
13138b5b1575
149315a13cd
15549b3aed0
hex32b281279

13608948345 has 8 divisors (see below), whose sum is σ = 21774317376. Its totient is φ = 7258105776.

The previous prime is 13608948343. The next prime is 13608948347. The reversal of 13608948345 is 54384980631.

It is an interprime number because it is at equal distance from previous prime (13608948343) and next prime (13608948347).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13608948345 - 21 = 13608948343 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13608948343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 453631597 + ... + 453631626.

It is an arithmetic number, because the mean of its divisors is an integer number (2721789672).

Almost surely, 213608948345 is an apocalyptic number.

13608948345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13608948345 is a deficient number, since it is larger than the sum of its proper divisors (8165369031).

13608948345 is an equidigital number, since it uses as much as digits as its factorization.

13608948345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 907263231.

The product of its (nonzero) digits is 2488320, while the sum is 51.

The spelling of 13608948345 in words is "thirteen billion, six hundred eight million, nine hundred forty-eight thousand, three hundred forty-five".

Divisors: 1 3 5 15 907263223 2721789669 4536316115 13608948345