Base | Representation |
---|---|
bin | 11001010110010100… |
… | …00001001001111001 |
3 | 1022010102122012112220 |
4 | 30223022001021321 |
5 | 210332342321340 |
6 | 10130222554253 |
7 | 661146103146 |
oct | 145312011171 |
9 | 38112565486 |
10 | 13608948345 |
11 | 5853995353 |
12 | 2779738989 |
13 | 138b5b1575 |
14 | 9315a13cd |
15 | 549b3aed0 |
hex | 32b281279 |
13608948345 has 8 divisors (see below), whose sum is σ = 21774317376. Its totient is φ = 7258105776.
The previous prime is 13608948343. The next prime is 13608948347. The reversal of 13608948345 is 54384980631.
It is an interprime number because it is at equal distance from previous prime (13608948343) and next prime (13608948347).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13608948345 - 21 = 13608948343 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13608948343) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 453631597 + ... + 453631626.
It is an arithmetic number, because the mean of its divisors is an integer number (2721789672).
Almost surely, 213608948345 is an apocalyptic number.
13608948345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13608948345 is a deficient number, since it is larger than the sum of its proper divisors (8165369031).
13608948345 is an equidigital number, since it uses as much as digits as its factorization.
13608948345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 907263231.
The product of its (nonzero) digits is 2488320, while the sum is 51.
The spelling of 13608948345 in words is "thirteen billion, six hundred eight million, nine hundred forty-eight thousand, three hundred forty-five".
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