Base | Representation |
---|---|
bin | 111111010111110100… |
… | …0000101010100100101 |
3 | 111000021101022000220212 |
4 | 1332233220011110211 |
5 | 4212203132202113 |
6 | 142304043505205 |
7 | 12555310135112 |
oct | 1765750052445 |
9 | 430241260825 |
10 | 136090506533 |
11 | 527965a7903 |
12 | 22460528205 |
13 | caaa93bc57 |
14 | 6830317909 |
15 | 38178c80a8 |
hex | 1fafa05525 |
136090506533 has 2 divisors, whose sum is σ = 136090506534. Its totient is φ = 136090506532.
The previous prime is 136090506511. The next prime is 136090506593. The reversal of 136090506533 is 335605090631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129702980449 + 6387526084 = 360143^2 + 79922^2 .
It is a cyclic number.
It is not a de Polignac number, because 136090506533 - 214 = 136090490149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136090506593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68045253266 + 68045253267.
It is an arithmetic number, because the mean of its divisors is an integer number (68045253267).
Almost surely, 2136090506533 is an apocalyptic number.
It is an amenable number.
136090506533 is a deficient number, since it is larger than the sum of its proper divisors (1).
136090506533 is an equidigital number, since it uses as much as digits as its factorization.
136090506533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 218700, while the sum is 41.
The spelling of 136090506533 in words is "one hundred thirty-six billion, ninety million, five hundred six thousand, five hundred thirty-three".
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