Base | Representation |
---|---|
bin | 11110111100100011010111… |
… | …110010100100011100000011 |
3 | 122211220021110022020110212011 |
4 | 132330203113302210130003 |
5 | 120314401002233033124 |
6 | 1201244351235313351 |
7 | 40445040630134566 |
oct | 3674432762443403 |
9 | 584807408213764 |
10 | 136102544033539 |
11 | 3a403845a14836 |
12 | 1332170274b857 |
13 | 5ac35515005b5 |
14 | 2587580c424dd |
15 | 10b0515c93994 |
hex | 7bc8d7ca4703 |
136102544033539 has 32 divisors (see below), whose sum is σ = 139945544363520. Its totient is φ = 132329695680000.
The previous prime is 136102544033537. The next prime is 136102544033581. The reversal of 136102544033539 is 935330445201631.
It is a cyclic number.
It is not a de Polignac number, because 136102544033539 - 21 = 136102544033537 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 136102544033492 and 136102544033501.
It is not an unprimeable number, because it can be changed into a prime (136102544033537) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 791718907 + ... + 791890795.
It is an arithmetic number, because the mean of its divisors is an integer number (4373298261360).
Almost surely, 2136102544033539 is an apocalyptic number.
136102544033539 is a deficient number, since it is larger than the sum of its proper divisors (3843000329981).
136102544033539 is a wasteful number, since it uses less digits than its factorization.
136102544033539 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 172651.
The product of its (nonzero) digits is 3499200, while the sum is 49.
The spelling of 136102544033539 in words is "one hundred thirty-six trillion, one hundred two billion, five hundred forty-four million, thirty-three thousand, five hundred thirty-nine".
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