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136102544033647 is a prime number
BaseRepresentation
bin11110111100100011010111…
…110010100100011101101111
3122211220021110022020111000011
4132330203113302210131233
5120314401002233034042
61201244351235314051
740445040630135112
oct3674432762443557
9584807408214004
10136102544033647
113a403845a14924
121332170274b927
135ac3551500669
142587580c42579
1510b0515c93a17
hex7bc8d7ca476f

136102544033647 has 2 divisors, whose sum is σ = 136102544033648. Its totient is φ = 136102544033646.

The previous prime is 136102544033581. The next prime is 136102544033689. The reversal of 136102544033647 is 746330445201631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 136102544033647 - 211 = 136102544031599 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 136102544033647.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136102544733647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68051272016823 + 68051272016824.

It is an arithmetic number, because the mean of its divisors is an integer number (68051272016824).

Almost surely, 2136102544033647 is an apocalyptic number.

136102544033647 is a deficient number, since it is larger than the sum of its proper divisors (1).

136102544033647 is an equidigital number, since it uses as much as digits as its factorization.

136102544033647 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4354560, while the sum is 49.

The spelling of 136102544033647 in words is "one hundred thirty-six trillion, one hundred two billion, five hundred forty-four million, thirty-three thousand, six hundred forty-seven".