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1361030131141 is a prime number
BaseRepresentation
bin10011110011100011101…
…101111010110111000101
311211010001112022100020121
4103303203231322313011
5134244342203144031
62521125411101541
7200221411143022
oct23634355726705
94733045270217
101361030131141
11485234032aaa
1219b93a2a18b1
139b4630b1385
1449c34b90549
152560bd0c011
hex13ce3b7adc5

1361030131141 has 2 divisors, whose sum is σ = 1361030131142. Its totient is φ = 1361030131140.

The previous prime is 1361030131091. The next prime is 1361030131187. The reversal of 1361030131141 is 1411310301631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1140431768100 + 220598363041 = 1067910^2 + 469679^2 .

It is a cyclic number.

It is not a de Polignac number, because 1361030131141 - 217 = 1361030000069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1361030131841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680515065570 + 680515065571.

It is an arithmetic number, because the mean of its divisors is an integer number (680515065571).

Almost surely, 21361030131141 is an apocalyptic number.

It is an amenable number.

1361030131141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361030131141 is an equidigital number, since it uses as much as digits as its factorization.

1361030131141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 1361030131141 its reverse (1411310301631), we get a palindrome (2772340432772).

The spelling of 1361030131141 in words is "one trillion, three hundred sixty-one billion, thirty million, one hundred thirty-one thousand, one hundred forty-one".