Base | Representation |
---|---|
bin | 10011110011101101111… |
… | …111101000010101100111 |
3 | 11211010111112201220222222 |
4 | 103303231333220111213 |
5 | 134300220322433043 |
6 | 2521154450342555 |
7 | 200225603510225 |
oct | 23635577502547 |
9 | 4733445656888 |
10 | 1361202546023 |
11 | 485312394941 |
12 | 19b987b8aa5b |
13 | 9b48ca2a908 |
14 | 49c4da31b15 |
15 | 2561c017d68 |
hex | 13cedfe8567 |
1361202546023 has 4 divisors (see below), whose sum is σ = 1361209767840. Its totient is φ = 1361195324208.
The previous prime is 1361202545939. The next prime is 1361202546043. The reversal of 1361202546023 is 3206452021631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1361202546023 - 28 = 1361202545767 is a prime.
It is a super-3 number, since 3×13612025460233 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1361202546043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3320390 + ... + 3707747.
It is an arithmetic number, because the mean of its divisors is an integer number (340302441960).
Almost surely, 21361202546023 is an apocalyptic number.
1361202546023 is a deficient number, since it is larger than the sum of its proper divisors (7221817).
1361202546023 is an equidigital number, since it uses as much as digits as its factorization.
1361202546023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7221816.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 1361202546023 its reverse (3206452021631), we get a palindrome (4567654567654).
The spelling of 1361202546023 in words is "one trillion, three hundred sixty-one billion, two hundred two million, five hundred forty-six thousand, twenty-three".
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