136124253433 has 8 divisors (see below), whose sum is σ = 155628066752. Its totient is φ = 116634812976.

The previous prime is 136124253431. The next prime is 136124253437. The reversal of 136124253433 is 334352421631.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 136124253433 - 2¹ = 136124253431 is a prime.

It is a super-2 number, since 2×136124253433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 136124253392 and 136124253401.

It is not an unprimeable number, because it can be changed into a prime (136124253431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3572910 + ... + 3610807.

It is an arithmetic number, because the mean of its divisors is an integer number (19453508344).

Almost surely, 2^136124253433 is an apocalyptic number.

It is an amenable number.

136124253433 is a deficient number, since it is larger than the sum of its proper divisors (19503813319).

136124253433 is an equidigital number, since it uses as much as digits as its factorization.

136124253433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7186431.

The product of its digits is 155520, while the sum is 37.

The spelling of 136124253433 in words is "one hundred thirty-six billion, one hundred twenty-four million, two hundred fifty-three thousand, four hundred thirty-three".