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1361247774031 is a prime number
BaseRepresentation
bin10011110011110000101…
…100001010010101001111
311211010121200211202011101
4103303300230022111033
5134300313412232111
62521203144003531
7200226663111265
oct23636054122517
94733550752141
101361247774031
11485335976362
1219b99b1605a7
139b499204c52
1449c55a46435
1525620e9dbc1
hex13cf0b0a54f

1361247774031 has 2 divisors, whose sum is σ = 1361247774032. Its totient is φ = 1361247774030.

The previous prime is 1361247774017. The next prime is 1361247774037. The reversal of 1361247774031 is 1304777421631.

It is a strong prime.

It is an emirp because it is prime and its reverse (1304777421631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1361247774031 - 215 = 1361247741263 is a prime.

It is a super-2 number, since 2×13612477740312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1361247774037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680623887015 + 680623887016.

It is an arithmetic number, because the mean of its divisors is an integer number (680623887016).

Almost surely, 21361247774031 is an apocalyptic number.

1361247774031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361247774031 is an equidigital number, since it uses as much as digits as its factorization.

1361247774031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 592704, while the sum is 46.

The spelling of 1361247774031 in words is "one trillion, three hundred sixty-one billion, two hundred forty-seven million, seven hundred seventy-four thousand, thirty-one".