1361250353731 has 2 divisors, whose sum is σ = 1361250353732. Its totient is φ = 1361250353730.

The previous prime is 1361250353717. The next prime is 1361250353803. The reversal of 1361250353731 is 1373530521631.

It is a weak prime.

It is an emirp because it is prime and its reverse (1373530521631) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1361250353731 is a prime.

It is a super-2 number, since 2×1361250353731² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1361250353711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680625176865 + 680625176866.

It is an arithmetic number, because the mean of its divisors is an integer number (680625176866).

Almost surely, 2^{1361250353731} is an apocalyptic number.

1361250353731 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361250353731 is an equidigital number, since it uses as much as digits as its factorization.

1361250353731 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 170100, while the sum is 40.

The spelling of 1361250353731 in words is "one trillion, three hundred sixty-one billion, two hundred fifty million, three hundred fifty-three thousand, seven hundred thirty-one".