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13612541243395 = 523891139601611
BaseRepresentation
bin1100011000010110101010…
…1011110111000000000011
31210012100100101220202110211
43012011222223313000003
53241011441024242040
644541303133134551
72603321314304263
oct306055253670003
953170311822424
1013612541243395
114379056721056
12163a25062a457
13779870942cb3
14350bc9b377a3
151891605388ea
hexc616aaf7003

13612541243395 has 8 divisors (see below), whose sum is σ = 16341887116080. Its totient is φ = 10885474578720.

The previous prime is 13612541243393. The next prime is 13612541243459. The reversal of 13612541243395 is 59334214521631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13612541243395 - 21 = 13612541243393 is a prime.

It is a super-2 number, since 2×136125412433952 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13612541243393) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 569788861 + ... + 569812750.

It is an arithmetic number, because the mean of its divisors is an integer number (2042735889510).

Almost surely, 213612541243395 is an apocalyptic number.

13612541243395 is a deficient number, since it is larger than the sum of its proper divisors (2729345872685).

13612541243395 is a wasteful number, since it uses less digits than its factorization.

13612541243395 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1139604005.

The product of its digits is 2332800, while the sum is 49.

The spelling of 13612541243395 in words is "thirteen trillion, six hundred twelve billion, five hundred forty-one million, two hundred forty-three thousand, three hundred ninety-five".

Divisors: 1 5 2389 11945 1139601611 5698008055 2722508248679 13612541243395