Base | Representation |
---|---|
bin | 1100011000010110101010… |
… | …1011110111000000000011 |
3 | 1210012100100101220202110211 |
4 | 3012011222223313000003 |
5 | 3241011441024242040 |
6 | 44541303133134551 |
7 | 2603321314304263 |
oct | 306055253670003 |
9 | 53170311822424 |
10 | 13612541243395 |
11 | 4379056721056 |
12 | 163a25062a457 |
13 | 779870942cb3 |
14 | 350bc9b377a3 |
15 | 1891605388ea |
hex | c616aaf7003 |
13612541243395 has 8 divisors (see below), whose sum is σ = 16341887116080. Its totient is φ = 10885474578720.
The previous prime is 13612541243393. The next prime is 13612541243459. The reversal of 13612541243395 is 59334214521631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13612541243395 - 21 = 13612541243393 is a prime.
It is a super-2 number, since 2×136125412433952 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13612541243393) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 569788861 + ... + 569812750.
It is an arithmetic number, because the mean of its divisors is an integer number (2042735889510).
Almost surely, 213612541243395 is an apocalyptic number.
13612541243395 is a deficient number, since it is larger than the sum of its proper divisors (2729345872685).
13612541243395 is a wasteful number, since it uses less digits than its factorization.
13612541243395 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1139604005.
The product of its digits is 2332800, while the sum is 49.
The spelling of 13612541243395 in words is "thirteen trillion, six hundred twelve billion, five hundred forty-one million, two hundred forty-three thousand, three hundred ninety-five".
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