Base | Representation |
---|---|
bin | 10011110011110001101… |
… | …001000101100000100111 |
3 | 11211010122210220011022002 |
4 | 103303301221011200213 |
5 | 134300332004320223 |
6 | 2521204514155515 |
7 | 200230245630125 |
oct | 23636151054047 |
9 | 4733583804262 |
10 | 1361263745063 |
11 | 485343994662 |
12 | 19b9a4582b9b |
13 | 9b49c607571 |
14 | 49c57c02915 |
15 | 256225a5e28 |
hex | 13cf1a45827 |
1361263745063 has 2 divisors, whose sum is σ = 1361263745064. Its totient is φ = 1361263745062.
The previous prime is 1361263745057. The next prime is 1361263745087. The reversal of 1361263745063 is 3605473621631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1361263745063 - 228 = 1360995309607 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1361263744999 and 1361263745017.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1361263765063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680631872531 + 680631872532.
It is an arithmetic number, because the mean of its divisors is an integer number (680631872532).
Almost surely, 21361263745063 is an apocalyptic number.
1361263745063 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361263745063 is an equidigital number, since it uses as much as digits as its factorization.
1361263745063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1632960, while the sum is 47.
The spelling of 1361263745063 in words is "one trillion, three hundred sixty-one billion, two hundred sixty-three million, seven hundred forty-five thousand, sixty-three".
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