Base | Representation |
---|---|
bin | 10011110011110001101… |
… | …010001000111111100011 |
3 | 11211010122211102012110120 |
4 | 103303301222020333203 |
5 | 134300332042141400 |
6 | 2521204524131323 |
7 | 200230251161031 |
oct | 23636152107743 |
9 | 4733584365416 |
10 | 1361264021475 |
11 | 4853440632a6 |
12 | 19b9a4696b43 |
13 | 9b49c6a3317 |
14 | 49c57c75551 |
15 | 2562260cca0 |
hex | 13cf1a88fe3 |
1361264021475 has 48 divisors (see below), whose sum is σ = 2303790500352. Its totient is φ = 708868863360.
The previous prime is 1361264021443. The next prime is 1361264021527. The reversal of 1361264021475 is 5741204621631.
It is not a de Polignac number, because 1361264021475 - 25 = 1361264021443 is a prime.
It is a super-2 number, since 2×13612640214752 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9074934 + ... + 9223716.
It is an arithmetic number, because the mean of its divisors is an integer number (47995635424).
Almost surely, 21361264021475 is an apocalyptic number.
1361264021475 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1361264021475 is a deficient number, since it is larger than the sum of its proper divisors (942526478877).
1361264021475 is a wasteful number, since it uses less digits than its factorization.
1361264021475 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151676 (or 151671 counting only the distinct ones).
The product of its (nonzero) digits is 241920, while the sum is 42.
The spelling of 1361264021475 in words is "one trillion, three hundred sixty-one billion, two hundred sixty-four million, twenty-one thousand, four hundred seventy-five".
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