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136135463313301 = 160784714040643
BaseRepresentation
bin11110111101000010000001…
…111011101001111110010101
3122212000102102111200011012221
4132331002001323221332111
5120320420412102011201
61201311433553542341
740450314455323264
oct3675020173517625
9585012374604187
10136135463313301
113a4167a8aa5971
1213327b6b2749b1
135ac6699626a6a
142588dc4c805db
1510b12e0d194a1
hex7bd081ee9f95

136135463313301 has 4 divisors (see below), whose sum is σ = 136220177355552. Its totient is φ = 136050749271052.

The previous prime is 136135463313287. The next prime is 136135463313319. The reversal of 136135463313301 is 103313364531631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 136135463313301 - 239 = 135585707499413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136135463313331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42357018715 + ... + 42357021928.

It is an arithmetic number, because the mean of its divisors is an integer number (34055044338888).

Almost surely, 2136135463313301 is an apocalyptic number.

It is an amenable number.

136135463313301 is a deficient number, since it is larger than the sum of its proper divisors (84714042251).

136135463313301 is an equidigital number, since it uses as much as digits as its factorization.

136135463313301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84714042250.

The product of its (nonzero) digits is 524880, while the sum is 43.

The spelling of 136135463313301 in words is "one hundred thirty-six trillion, one hundred thirty-five billion, four hundred sixty-three million, three hundred thirteen thousand, three hundred one".

Divisors: 1 1607 84714040643 136135463313301