Base | Representation |
---|---|
bin | 10011110011111011110… |
… | …111110000001111011110 |
3 | 11211011002202211012211221 |
4 | 103303323313300033132 |
5 | 134301204423043040 |
6 | 2521233524403554 |
7 | 200234431432624 |
oct | 23637367601736 |
9 | 4734082735757 |
10 | 1361435362270 |
11 | 485421851165 |
12 | 19ba31b465ba |
13 | 9b4c90349c9 |
14 | 49c72917514 |
15 | 256326a574a |
hex | 13cfbdf03de |
1361435362270 has 32 divisors (see below), whose sum is σ = 2492571916800. Its totient is φ = 535309362720.
The previous prime is 1361435362223. The next prime is 1361435362279. The reversal of 1361435362270 is 722635341631.
It is a super-2 number, since 2×13614353622702 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1361435362279) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3956146 + ... + 4286485.
It is an arithmetic number, because the mean of its divisors is an integer number (77892872400).
Almost surely, 21361435362270 is an apocalyptic number.
1361435362270 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1361435362270 is a deficient number, since it is larger than the sum of its proper divisors (1131136554530).
1361435362270 is a wasteful number, since it uses less digits than its factorization.
1361435362270 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8242920.
The product of its (nonzero) digits is 544320, while the sum is 43.
The spelling of 1361435362270 in words is "one trillion, three hundred sixty-one billion, four hundred thirty-five million, three hundred sixty-two thousand, two hundred seventy".
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