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136190447 is a prime number
BaseRepresentation
bin10000001111000…
…01100111101111
3100111021012011122
420013201213233
5234331043242
621303011155
73242412461
oct1007414757
9314235148
10136190447
116a96a998
1239739abb
13222a5383
1414132131
15be52ad2
hex81e19ef

136190447 has 2 divisors, whose sum is σ = 136190448. Its totient is φ = 136190446.

The previous prime is 136190441. The next prime is 136190459. The reversal of 136190447 is 744091631.

It is a weak prime.

It is an emirp because it is prime and its reverse (744091631) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136190447 is a prime.

It is a super-3 number, since 3×1361904473 (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136190441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68095223 + 68095224.

It is an arithmetic number, because the mean of its divisors is an integer number (68095224).

Almost surely, 2136190447 is an apocalyptic number.

136190447 is a deficient number, since it is larger than the sum of its proper divisors (1).

136190447 is an equidigital number, since it uses as much as digits as its factorization.

136190447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 35.

The square root of 136190447 is about 11670.0662808743. The cubic root of 136190447 is about 514.4962516919.

The spelling of 136190447 in words is "one hundred thirty-six million, one hundred ninety thousand, four hundred forty-seven".