Base | Representation |
---|---|
bin | 111111011010111001… |
… | …1011101110010100110 |
3 | 111000112121022212000112 |
4 | 1332311303131302212 |
5 | 4212411200404023 |
6 | 142322225213022 |
7 | 12561006130214 |
oct | 1766563356246 |
9 | 430477285015 |
10 | 136194153638 |
11 | 5283a05a474 |
12 | 2248b191172 |
13 | cac625b7ba |
14 | 683ddb7cb4 |
15 | 3821a4d478 |
hex | 1fb5cddca6 |
136194153638 has 4 divisors (see below), whose sum is σ = 204291230460. Its totient is φ = 68097076818.
The previous prime is 136194153607. The next prime is 136194153647. The reversal of 136194153638 is 836351491631.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 836351491631 = 44711 ⋅18705721.
It is a super-2 number, since 2×1361941536382 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34048538408 + ... + 34048538411.
It is an arithmetic number, because the mean of its divisors is an integer number (51072807615).
Almost surely, 2136194153638 is an apocalyptic number.
136194153638 is a deficient number, since it is larger than the sum of its proper divisors (68097076822).
136194153638 is an equidigital number, since it uses as much as digits as its factorization.
136194153638 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68097076821.
The product of its digits is 1399680, while the sum is 50.
The spelling of 136194153638 in words is "one hundred thirty-six billion, one hundred ninety-four million, one hundred fifty-three thousand, six hundred thirty-eight".
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